Base | Representation |
---|---|
bin | 100101001100001001010… |
… | …1111100110100111111101 |
3 | 200002122020001210002001111 |
4 | 1022120102233212213331 |
5 | 1132220443320113401 |
6 | 14512035513242021 |
7 | 1035165261222100 |
oct | 112302257464775 |
9 | 20078201702044 |
10 | 5111325551101 |
11 | 16a0779026850 |
12 | 6a6738703311 |
13 | 2b0cc40a4123 |
14 | 139564a1c737 |
15 | 8ce55da4e51 |
hex | 4a612be69fd |
5111325551101 has 24 divisors (see below), whose sum is σ = 6488114492736. Its totient is φ = 3981772206720.
The previous prime is 5111325551099. The next prime is 5111325551117. The reversal of 5111325551101 is 1011555231115.
It is not a de Polignac number, because 5111325551101 - 21 = 5111325551099 is a prime.
It is a super-2 number, since 2×51113255511012 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5111325551131) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 710160 + ... + 3275206.
It is an arithmetic number, because the mean of its divisors is an integer number (270338103864).
Almost surely, 25111325551101 is an apocalyptic number.
It is an amenable number.
5111325551101 is a deficient number, since it is larger than the sum of its proper divisors (1376788941635).
5111325551101 is a wasteful number, since it uses less digits than its factorization.
5111325551101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2568769 (or 2568762 counting only the distinct ones).
The product of its (nonzero) digits is 3750, while the sum is 31.
The spelling of 5111325551101 in words is "five trillion, one hundred eleven billion, three hundred twenty-five million, five hundred fifty-one thousand, one hundred one".
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