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5111334241131 = 31703778080377
BaseRepresentation
bin100101001100001001101…
…0000110000001101101011
3200002122020200010120112110
41022120103100300031223
51132221003031204011
614512040423413403
71035165425124336
oct112302320601553
920078220116473
105111334241131
1116a0782a21798
126a673b5b4263
132b0cc5b27661
14139565c4161d
158ce56a1eba6
hex4a61343036b

5111334241131 has 4 divisors (see below), whose sum is σ = 6815112321512. Its totient is φ = 3407556160752.

The previous prime is 5111334241127. The next prime is 5111334241147. The reversal of 5111334241131 is 1311424331115.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 5111334241131 - 22 = 5111334241127 is a prime.

It is a super-2 number, since 2×51113342411312 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5111334241031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 851889040186 + ... + 851889040191.

It is an arithmetic number, because the mean of its divisors is an integer number (1703778080378).

Almost surely, 25111334241131 is an apocalyptic number.

5111334241131 is a deficient number, since it is larger than the sum of its proper divisors (1703778080381).

5111334241131 is a wasteful number, since it uses less digits than its factorization.

5111334241131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1703778080380.

The product of its digits is 4320, while the sum is 30.

Adding to 5111334241131 its reverse (1311424331115), we get a palindrome (6422758572246).

The spelling of 5111334241131 in words is "five trillion, one hundred eleven billion, three hundred thirty-four million, two hundred forty-one thousand, one hundred thirty-one".

Divisors: 1 3 1703778080377 5111334241131