Base | Representation |
---|---|
bin | 100101001100001011111… |
… | …1101101010110011010110 |
3 | 200002122110011120020220200 |
4 | 1022120113331222303112 |
5 | 1132221133224434220 |
6 | 14512052322241330 |
7 | 1035200403456423 |
oct | 112302775526326 |
9 | 20078404506820 |
10 | 5111413124310 |
11 | 16a08134aa8a9 |
12 | 6a6761ab6246 |
13 | 2b10092865ac |
14 | 1395724d6d4a |
15 | 8ce5d902890 |
hex | 4a617f6acd6 |
5111413124310 has 96 divisors (see below), whose sum is σ = 13670078123520. Its totient is φ = 1324444993344.
The previous prime is 5111413124219. The next prime is 5111413124381. The reversal of 5111413124310 is 134213141115.
5111413124310 is a `hidden beast` number, since 5 + 1 + 1 + 1 + 413 + 1 + 243 + 1 + 0 = 666.
It is a super-2 number, since 2×51114131243102 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3758692 + ... + 4934631.
It is an arithmetic number, because the mean of its divisors is an integer number (142396647120).
Almost surely, 25111413124310 is an apocalyptic number.
5111413124310 is an abundant number, since it is smaller than the sum of its proper divisors (8558664999210).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5111413124310 is a wasteful number, since it uses less digits than its factorization.
5111413124310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8693522 (or 8693519 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 27.
Adding to 5111413124310 its reverse (134213141115), we get a palindrome (5245626265425).
The spelling of 5111413124310 in words is "five trillion, one hundred eleven billion, four hundred thirteen million, one hundred twenty-four thousand, three hundred ten".
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