Base | Representation |
---|---|
bin | 100101001100001100010… |
… | …0000011100100101011011 |
3 | 200002122110210201102211010 |
4 | 1022120120200130211123 |
5 | 1132221143043203430 |
6 | 14512053245505003 |
7 | 1035200544120141 |
oct | 112303040344533 |
9 | 20078423642733 |
10 | 5111422241115 |
11 | 16a0818667453 |
12 | 6a6764b72163 |
13 | 2b100b129158 |
14 | 1395737cb591 |
15 | 8ce5e603cb0 |
hex | 4a61881c95b |
5111422241115 has 32 divisors (see below), whose sum is σ = 8350820191296. Its totient is φ = 2669122160640.
The previous prime is 5111422241071. The next prime is 5111422241131.
It is a happy number.
5111422241115 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 5111422241115 - 213 = 5111422232923 is a prime.
It is a super-2 number, since 2×51114222411152 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16886356 + ... + 17186385.
It is an arithmetic number, because the mean of its divisors is an integer number (260963130978).
Almost surely, 25111422241115 is an apocalyptic number.
5111422241115 is a deficient number, since it is larger than the sum of its proper divisors (3239397950181).
5111422241115 is a wasteful number, since it uses less digits than its factorization.
5111422241115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34072959.
The product of its digits is 3200, while the sum is 30.
The spelling of 5111422241115 in words is "five trillion, one hundred eleven billion, four hundred twenty-two million, two hundred forty-one thousand, one hundred fifteen".
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