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5111554417 is a prime number
BaseRepresentation
bin1001100001010110…
…00010000101110001
3111012020021212110021
410300223002011301
540432024220132
62203114203441
7240445332004
oct46053020561
914166255407
105111554417
112193380542
12ba7a23581
13635cb9618
14366c1d53b
151edb3e997
hex130ac2171

5111554417 has 2 divisors, whose sum is σ = 5111554418. Its totient is φ = 5111554416.

The previous prime is 5111554387. The next prime is 5111554451. The reversal of 5111554417 is 7144551115.

It is an a-pointer prime, because the next prime (5111554451) can be obtained adding 5111554417 to its sum of digits (34).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5014905856 + 96648561 = 70816^2 + 9831^2 .

It is a cyclic number.

It is not a de Polignac number, because 5111554417 - 27 = 5111554289 is a prime.

It is a super-2 number, since 2×51115544172 = 52255977115904419778, which contains 22 as substring.

It is a weakly prime.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555777208 + 2555777209.

It is an arithmetic number, because the mean of its divisors is an integer number (2555777209).

Almost surely, 25111554417 is an apocalyptic number.

It is an amenable number.

5111554417 is a deficient number, since it is larger than the sum of its proper divisors (1).

5111554417 is an equidigital number, since it uses as much as digits as its factorization.

5111554417 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 14000, while the sum is 34.

The square root of 5111554417 is about 71495.1356177468. The cubic root of 5111554417 is about 1722.5995504209.

The spelling of 5111554417 in words is "five billion, one hundred eleven million, five hundred fifty-four thousand, four hundred seventeen".