Base | Representation |
---|---|
bin | 101111100110111111… |
… | …011000001010111100 |
3 | 11212221122022210000022 |
4 | 233212333120022330 |
5 | 1314143210422022 |
6 | 35252331151312 |
7 | 3456541643504 |
oct | 574677301274 |
9 | 155848283008 |
10 | 51120014012 |
11 | 1a752a08171 |
12 | 9aa7ba5538 |
13 | 4a88b0a302 |
14 | 268d39ca04 |
15 | 14e2d80c42 |
hex | be6fd82bc |
51120014012 has 6 divisors (see below), whose sum is σ = 89460024528. Its totient is φ = 25560007004.
The previous prime is 51120014003. The next prime is 51120014017. The reversal of 51120014012 is 21041002115.
It is a super-2 number, since 2×511200140122 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51120014017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6390001748 + ... + 6390001755.
It is an arithmetic number, because the mean of its divisors is an integer number (14910004088).
Almost surely, 251120014012 is an apocalyptic number.
It is an amenable number.
51120014012 is a deficient number, since it is larger than the sum of its proper divisors (38340010516).
51120014012 is a wasteful number, since it uses less digits than its factorization.
51120014012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12780003507 (or 12780003505 counting only the distinct ones).
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 51120014012 its reverse (21041002115), we get a palindrome (72161016127).
The spelling of 51120014012 in words is "fifty-one billion, one hundred twenty million, fourteen thousand, twelve".
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