5112140333 has 4 divisors (see below), whose sum is σ = 5334407328. Its totient is φ = 4889873340.

The previous prime is 5112140317. The next prime is 5112140359. The reversal of 5112140333 is 3330412115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5112140333 - 2⁴ = 5112140317 is a prime.

It is a super-2 number, since 2×5112140333² = 52267957568570701778, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (23), and also a Moran number because the ratio is a prime number: 222266971 = 5112140333 / (5 + 1 + 1 + 2 + 1 + 4 + 0 + 3 + 3 + 3).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5112140299 and 5112140308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5112140633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111133463 + ... + 111133508.

It is an arithmetic number, because the mean of its divisors is an integer number (1333601832).

Almost surely, 2^5112140333 is an apocalyptic number.

It is an amenable number.

5112140333 is a deficient number, since it is larger than the sum of its proper divisors (222266995).

5112140333 is a wasteful number, since it uses less digits than its factorization.

5112140333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 222266994.

The product of its (nonzero) digits is 1080, while the sum is 23.

The square root of 5112140333 is about 71499.2330937892. The cubic root of 5112140333 is about 1722.6653660218.

Adding to 5112140333 its reverse (3330412115), we get a palindrome (8442552448).

The spelling of 5112140333 in words is "five billion, one hundred twelve million, one hundred forty thousand, three hundred thirty-three".