Base | Representation |
---|---|
bin | 100101001100100011110… |
… | …0001100001011111110111 |
3 | 200002201111210000012122220 |
4 | 1022121013201201133313 |
5 | 1132224302012140120 |
6 | 14512303424453423 |
7 | 1035226232653656 |
oct | 112310741413767 |
9 | 20081453005586 |
10 | 5112211052535 |
11 | 16a1092956114 |
12 | 6a694517a273 |
13 | 2b1105692482 |
14 | 13960a48319d |
15 | 8cea89bab40 |
hex | 4a6478617f7 |
5112211052535 has 16 divisors (see below), whose sum is σ = 8179985361120. Its totient is φ = 2726363335680.
The previous prime is 5112211052527. The next prime is 5112211052677. The reversal of 5112211052535 is 5352501122115.
It is not a de Polignac number, because 5112211052535 - 23 = 5112211052527 is a prime.
It is a super-2 number, since 2×51122110525352 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5112211052496 and 5112211052505.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9043126 + ... + 9591795.
It is an arithmetic number, because the mean of its divisors is an integer number (511249085070).
Almost surely, 25112211052535 is an apocalyptic number.
5112211052535 is a deficient number, since it is larger than the sum of its proper divisors (3067774308585).
5112211052535 is a wasteful number, since it uses less digits than its factorization.
5112211052535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18653218.
The product of its (nonzero) digits is 15000, while the sum is 33.
The spelling of 5112211052535 in words is "five trillion, one hundred twelve billion, two hundred eleven million, fifty-two thousand, five hundred thirty-five".
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