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5112211052535 = 351828918634921
BaseRepresentation
bin100101001100100011110…
…0001100001011111110111
3200002201111210000012122220
41022121013201201133313
51132224302012140120
614512303424453423
71035226232653656
oct112310741413767
920081453005586
105112211052535
1116a1092956114
126a694517a273
132b1105692482
1413960a48319d
158cea89bab40
hex4a6478617f7

5112211052535 has 16 divisors (see below), whose sum is σ = 8179985361120. Its totient is φ = 2726363335680.

The previous prime is 5112211052527. The next prime is 5112211052677. The reversal of 5112211052535 is 5352501122115.

It is not a de Polignac number, because 5112211052535 - 23 = 5112211052527 is a prime.

It is a super-2 number, since 2×51122110525352 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5112211052496 and 5112211052505.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9043126 + ... + 9591795.

It is an arithmetic number, because the mean of its divisors is an integer number (511249085070).

Almost surely, 25112211052535 is an apocalyptic number.

5112211052535 is a deficient number, since it is larger than the sum of its proper divisors (3067774308585).

5112211052535 is a wasteful number, since it uses less digits than its factorization.

5112211052535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18653218.

The product of its (nonzero) digits is 15000, while the sum is 33.

The spelling of 5112211052535 in words is "five trillion, one hundred twelve billion, two hundred eleven million, fifty-two thousand, five hundred thirty-five".

Divisors: 1 3 5 15 18289 54867 91445 274335 18634921 55904763 93174605 279523815 340814070169 1022442210507 1704070350845 5112211052535