Base | Representation |
---|---|
bin | 1100001100000… |
… | …1000011101101 |
3 | 10120012021202201 |
4 | 3003001003231 |
5 | 101041404123 |
6 | 5023421501 |
7 | 1160350636 |
oct | 303010355 |
9 | 116167681 |
10 | 51122413 |
11 | 26948031 |
12 | 15154891 |
13 | a78c264 |
14 | 6b0a88d |
15 | 474c5ad |
hex | 30c10ed |
51122413 has 2 divisors, whose sum is σ = 51122414. Its totient is φ = 51122412.
The previous prime is 51122387. The next prime is 51122437. The reversal of 51122413 is 31422115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28111204 + 23011209 = 5302^2 + 4797^2 .
It is a cyclic number.
It is not a de Polignac number, because 51122413 - 25 = 51122381 is a prime.
It is a super-2 number, since 2×511224132 = 5227002221885138, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51122473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25561206 + 25561207.
It is an arithmetic number, because the mean of its divisors is an integer number (25561207).
Almost surely, 251122413 is an apocalyptic number.
It is an amenable number.
51122413 is a deficient number, since it is larger than the sum of its proper divisors (1).
51122413 is an equidigital number, since it uses as much as digits as its factorization.
51122413 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 240, while the sum is 19.
The square root of 51122413 is about 7149.9939160813. The cubic root of 51122413 is about 371.1394457438.
Adding to 51122413 its reverse (31422115), we get a palindrome (82544528).
The spelling of 51122413 in words is "fifty-one million, one hundred twenty-two thousand, four hundred thirteen".
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