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51122433 = 350933479
BaseRepresentation
bin1100001100000…
…1000100000001
310120012021210110
43003001010001
5101041404213
65023421533
71160350665
oct303010401
9116167713
1051122433
112694804a
12151548a9
13a78c27b
146b0a8a5
15474c5c3
hex30c1101

51122433 has 8 divisors (see below), whose sum is σ = 68299200. Its totient is φ = 34013648.

The previous prime is 51122413. The next prime is 51122437. The reversal of 51122433 is 33422115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 51122433 - 28 = 51122177 is a prime.

It is a super-2 number, since 2×511224332 = 5227006311678978, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (51122437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15213 + ... + 18266.

It is an arithmetic number, because the mean of its divisors is an integer number (8537400).

Almost surely, 251122433 is an apocalyptic number.

It is an amenable number.

51122433 is a deficient number, since it is larger than the sum of its proper divisors (17176767).

51122433 is a wasteful number, since it uses less digits than its factorization.

51122433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33991.

The product of its digits is 720, while the sum is 21.

The square root of 51122433 is about 7149.9953146838. The cubic root of 51122433 is about 371.1394941426.

Adding to 51122433 its reverse (33422115), we get a palindrome (84544548).

It can be divided in two parts, 5 and 1122433, that multiplied together give a palindrome (5612165).

The spelling of 51122433 in words is "fifty-one million, one hundred twenty-two thousand, four hundred thirty-three".

Divisors: 1 3 509 1527 33479 100437 17040811 51122433