Base | Representation |
---|---|
bin | 100101001100100110011… |
… | …1010010111001110001000 |
3 | 200002201202002002212211121 |
4 | 1022121030322113032020 |
5 | 1132224443132400440 |
6 | 14512320414205024 |
7 | 1035231411223534 |
oct | 112311472271610 |
9 | 20081662085747 |
10 | 5112301450120 |
11 | 16a1129989167 |
12 | 6a696b4b3774 |
13 | 2b111b323377 |
14 | 139618494bc4 |
15 | 8ceb18c534a |
hex | 4a64ce97388 |
5112301450120 has 64 divisors (see below), whose sum is σ = 11512889982000. Its totient is φ = 2043105804288.
The previous prime is 5112301450033. The next prime is 5112301450127. The reversal of 5112301450120 is 210541032115.
It can be written as a sum of positive squares in 8 ways, for example, as 1770139777156 + 3342161672964 = 1330466^2 + 1828158^2 .
It is a super-2 number, since 2×51123014501202 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (5112301450127) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 531806434 + ... + 531816046.
Almost surely, 25112301450120 is an apocalyptic number.
It is an amenable number.
5112301450120 is an abundant number, since it is smaller than the sum of its proper divisors (6400588531880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5112301450120 is a wasteful number, since it uses less digits than its factorization.
5112301450120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20042 (or 20038 counting only the distinct ones).
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 5112301450120 its reverse (210541032115), we get a palindrome (5322842482235).
The spelling of 5112301450120 in words is "five trillion, one hundred twelve billion, three hundred one million, four hundred fifty thousand, one hundred twenty".
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