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5112434301 = 313317413527
BaseRepresentation
bin1001100001011100…
…11000111001111101
3111012021221120102120
410300232120321331
540432240344201
62203145113153
7240455655162
oct46056307175
914167846376
105112434301
112193921617
12ba81887b9
13636236c70
14366dac069
151edc65536
hex130b98e7d

5112434301 has 16 divisors (see below), whose sum is σ = 7364106624. Its totient is φ = 3136181184.

The previous prime is 5112434267. The next prime is 5112434309. The reversal of 5112434301 is 1034342115.

It is a happy number.

It is not a de Polignac number, because 5112434301 - 26 = 5112434237 is a prime.

It is a super-2 number, since 2×51124343012 = 52273968964082717202, which contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5112434309) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 194401 + ... + 219126.

It is an arithmetic number, because the mean of its divisors is an integer number (460256664).

Almost surely, 25112434301 is an apocalyptic number.

It is an amenable number.

5112434301 is a deficient number, since it is larger than the sum of its proper divisors (2251672323).

5112434301 is a wasteful number, since it uses less digits than its factorization.

5112434301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 413860.

The product of its (nonzero) digits is 1440, while the sum is 24.

The square root of 5112434301 is about 71501.2888065663. The cubic root of 5112434301 is about 1722.6983853805.

Adding to 5112434301 its reverse (1034342115), we get a palindrome (6146776416).

The spelling of 5112434301 in words is "five billion, one hundred twelve million, four hundred thirty-four thousand, three hundred one".

Divisors: 1 3 13 39 317 951 4121 12363 413527 1240581 5375851 16127553 131088059 393264177 1704144767 5112434301