Base | Representation |
---|---|
bin | 10111001111111011011000… |
… | …00011111110110000101011 |
3 | 20201000111001211011221011212 |
4 | 23213331230003332300223 |
5 | 23200112102012111430 |
6 | 300422225103343335 |
7 | 13524434263605623 |
oct | 1347755403766053 |
9 | 221014054157155 |
10 | 51124808707115 |
11 | 15320a0076aa10 |
12 | 58983b6bb1b4b |
13 | 226b0832086b0 |
14 | c8a64d8a1883 |
15 | 5d9d185e8b95 |
hex | 2e7f6c0fec2b |
51124808707115 has 16 divisors (see below), whose sum is σ = 72075254793696. Its totient is φ = 34321549900800.
The previous prime is 51124808707087. The next prime is 51124808707117. The reversal of 51124808707115 is 51170780842115.
It is not a de Polignac number, because 51124808707115 - 226 = 51124741598251 is a prime.
It is a super-2 number, since 2×511248087071152 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (51124808707117) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 35751613766 + ... + 35751615195.
It is an arithmetic number, because the mean of its divisors is an integer number (4504703424606).
Almost surely, 251124808707115 is an apocalyptic number.
51124808707115 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
51124808707115 is a deficient number, since it is larger than the sum of its proper divisors (20950446086581).
51124808707115 is a wasteful number, since it uses less digits than its factorization.
51124808707115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71503228990.
The product of its (nonzero) digits is 627200, while the sum is 50.
The spelling of 51124808707115 in words is "fifty-one trillion, one hundred twenty-four billion, eight hundred eight million, seven hundred seven thousand, one hundred fifteen".
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