Base | Representation |
---|---|
bin | 100101001100101101101… |
… | …0000110010110100010110 |
3 | 200002202100212010211011012 |
4 | 1022121123100302310112 |
5 | 1132230441301230400 |
6 | 14512400334412222 |
7 | 1035240363526400 |
oct | 112313320626426 |
9 | 20082325124135 |
10 | 5112542211350 |
11 | 16a1242881692 |
12 | 6a6a18061072 |
13 | 2b115917c832 |
14 | 13963c447b70 |
15 | 8cec7ad1d35 |
hex | 4a65b432d16 |
5112542211350 has 72 divisors (see below), whose sum is σ = 11066424002640. Its totient is φ = 1752150294720.
The previous prime is 5112542211341. The next prime is 5112542211389. The reversal of 5112542211350 is 531122452115.
It is a super-2 number, since 2×51125422113502 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 5542511 + ... + 6398789.
It is an arithmetic number, because the mean of its divisors is an integer number (153700333370).
Almost surely, 25112542211350 is an apocalyptic number.
5112542211350 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
5112542211350 is an abundant number, since it is smaller than the sum of its proper divisors (5953881791290).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5112542211350 is a wasteful number, since it uses less digits than its factorization.
5112542211350 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 858742 (or 858730 counting only the distinct ones).
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 5112542211350 its reverse (531122452115), we get a palindrome (5643664663465).
The spelling of 5112542211350 in words is "five trillion, one hundred twelve billion, five hundred forty-two million, two hundred eleven thousand, three hundred fifty".
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