Base | Representation |
---|---|
bin | 1001100001011110… |
… | …01101110101011111 |
3 | 111012022100120211021 |
4 | 10300233031311133 |
5 | 40432314313403 |
6 | 2203153505011 |
7 | 240460550230 |
oct | 46057156537 |
9 | 14168316737 |
10 | 5112651103 |
11 | 2193a5a49a |
12 | ba8272167 |
13 | 6362b1851 |
14 | 367027087 |
15 | 1edca98bd |
hex | 130bcdd5f |
5112651103 has 4 divisors (see below), whose sum is σ = 5843029840. Its totient is φ = 4382272368.
The previous prime is 5112651017. The next prime is 5112651113. The reversal of 5112651103 is 3011562115.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5112651103 - 29 = 5112650591 is a prime.
It is a super-2 number, since 2×51126511032 = 52278402602014233218, which contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5112651113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 365189358 + ... + 365189371.
It is an arithmetic number, because the mean of its divisors is an integer number (1460757460).
Almost surely, 25112651103 is an apocalyptic number.
5112651103 is a deficient number, since it is larger than the sum of its proper divisors (730378737).
5112651103 is an equidigital number, since it uses as much as digits as its factorization.
5112651103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 730378736.
The product of its (nonzero) digits is 900, while the sum is 25.
The square root of 5112651103 is about 71502.8048610682. The cubic root of 5112651103 is about 1722.7227364139.
The spelling of 5112651103 in words is "five billion, one hundred twelve million, six hundred fifty-one thousand, one hundred three".
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