Base | Representation |
---|---|
bin | 100101001100110001100… |
… | …1111100101110101001011 |
3 | 200002202201012002202200221 |
4 | 1022121203033211311023 |
5 | 1132231230041114424 |
6 | 14512421520410511 |
7 | 1035243610632355 |
oct | 112314317456513 |
9 | 20082635082627 |
10 | 5112676113739 |
11 | 16a1301419517 |
12 | 6a6a54a76a37 |
13 | 2b117ab3360c |
14 | 1396521420d5 |
15 | 8ced47319e4 |
hex | 4a6633e5d4b |
5112676113739 has 2 divisors, whose sum is σ = 5112676113740. Its totient is φ = 5112676113738.
The previous prime is 5112676113679. The next prime is 5112676113803. The reversal of 5112676113739 is 9373116762115.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5112676113739 - 29 = 5112676113227 is a prime.
It is a super-2 number, since 2×51126761137392 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5112676113439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556338056869 + 2556338056870.
It is an arithmetic number, because the mean of its divisors is an integer number (2556338056870).
Almost surely, 25112676113739 is an apocalyptic number.
5112676113739 is a deficient number, since it is larger than the sum of its proper divisors (1).
5112676113739 is an equidigital number, since it uses as much as digits as its factorization.
5112676113739 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1428840, while the sum is 52.
The spelling of 5112676113739 in words is "five trillion, one hundred twelve billion, six hundred seventy-six million, one hundred thirteen thousand, seven hundred thirty-nine".
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