51127117 has 4 divisors (see below), whose sum is σ = 52214976. Its totient is φ = 50039260.

The previous prime is 51127103. The next prime is 51127121. The reversal of 51127117 is 71172115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51127117 - 2¹⁵ = 51094349 is a prime.

It is a super-2 number, since 2×51127117² = 5227964185463378, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51127091 and 51127100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51127127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 543859 + ... + 543952.

It is an arithmetic number, because the mean of its divisors is an integer number (13053744).

Almost surely, 2^51127117 is an apocalyptic number.

It is an amenable number.

51127117 is a deficient number, since it is larger than the sum of its proper divisors (1087859).

51127117 is a wasteful number, since it uses less digits than its factorization.

51127117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1087858.

The product of its digits is 490, while the sum is 25.

The square root of 51127117 is about 7150.3228598435. The cubic root of 51127117 is about 371.1508287903.

The spelling of 51127117 in words is "fifty-one million, one hundred twenty-seven thousand, one hundred seventeen".