Base | Representation |
---|---|
bin | 1001100001100000… |
… | …00010001011011101 |
3 | 111012022202110220221 |
4 | 10300300002023131 |
5 | 40432343144001 |
6 | 2203202241341 |
7 | 240462432262 |
oct | 46060021335 |
9 | 14168673827 |
10 | 5112865501 |
11 | 2194096587 |
12 | ba8356251 |
13 | 636358303 |
14 | 367081269 |
15 | 1edced1a1 |
hex | 130c022dd |
5112865501 has 2 divisors, whose sum is σ = 5112865502. Its totient is φ = 5112865500.
The previous prime is 5112865453. The next prime is 5112865519. The reversal of 5112865501 is 1055682115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3127717476 + 1985148025 = 55926^2 + 44555^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5112865501 is a prime.
It is a super-2 number, since 2×51128655012 = 52282787262631962002, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5112865001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556432750 + 2556432751.
It is an arithmetic number, because the mean of its divisors is an integer number (2556432751).
Almost surely, 25112865501 is an apocalyptic number.
It is an amenable number.
5112865501 is a deficient number, since it is larger than the sum of its proper divisors (1).
5112865501 is an equidigital number, since it uses as much as digits as its factorization.
5112865501 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12000, while the sum is 34.
The square root of 5112865501 is about 71504.3040732514. The cubic root of 5112865501 is about 1722.7468167549.
The spelling of 5112865501 in words is "five billion, one hundred twelve million, eight hundred sixty-five thousand, five hundred one".
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