Base | Representation |
---|---|
bin | 100101001100111011100… |
… | …1011001110101000010111 |
3 | 200002210120111100002020122 |
4 | 1022121313023032220113 |
5 | 1132232421142430310 |
6 | 14512515024022155 |
7 | 1035255111166514 |
oct | 112316713165027 |
9 | 20083514302218 |
10 | 5113010514455 |
11 | 16a1463159748 |
12 | 6a6b28a6195b |
13 | 2b12021b746c |
14 | 13968470c30b |
15 | 8d003c88555 |
hex | 4a6772cea17 |
5113010514455 has 32 divisors (see below), whose sum is σ = 6388394313600. Its totient is φ = 3923793119232.
The previous prime is 5113010514419. The next prime is 5113010514461. The reversal of 5113010514455 is 5544150103115.
It is not a de Polignac number, because 5113010514455 - 210 = 5113010513431 is a prime.
It is a super-2 number, since 2×51130105144552 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15274166 + ... + 15605324.
It is an arithmetic number, because the mean of its divisors is an integer number (199637322300).
Almost surely, 25113010514455 is an apocalyptic number.
5113010514455 is a deficient number, since it is larger than the sum of its proper divisors (1275383799145).
5113010514455 is a wasteful number, since it uses less digits than its factorization.
5113010514455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 331883.
The product of its (nonzero) digits is 30000, while the sum is 35.
The spelling of 5113010514455 in words is "five trillion, one hundred thirteen billion, ten million, five hundred fourteen thousand, four hundred fifty-five".
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