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5113142125015 = 51022628425003
BaseRepresentation
bin100101001100111111100…
…0001010010000111010111
3200002210220122222120222211
41022121333001102013113
51132233203341000030
614512540044534251
71035261266646001
oct112317701220727
920083818876884
105113142125015
1116a1520480701
126a6b64b51387
132b1223548032
14139697dab371
158d0105d412a
hex4a67f0521d7

5113142125015 has 4 divisors (see below), whose sum is σ = 6135770550024. Its totient is φ = 4090513700008.

The previous prime is 5113142124997. The next prime is 5113142125027. The reversal of 5113142125015 is 5105212413115.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5113142125015 is a prime.

It is a super-2 number, since 2×51131421250152 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 511314212497 + ... + 511314212506.

It is an arithmetic number, because the mean of its divisors is an integer number (1533942637506).

Almost surely, 25113142125015 is an apocalyptic number.

5113142125015 is a deficient number, since it is larger than the sum of its proper divisors (1022628425009).

5113142125015 is a wasteful number, since it uses less digits than its factorization.

5113142125015 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1022628425008.

The product of its (nonzero) digits is 6000, while the sum is 31.

The spelling of 5113142125015 in words is "five trillion, one hundred thirteen billion, one hundred forty-two million, one hundred twenty-five thousand, fifteen".

Divisors: 1 5 1022628425003 5113142125015