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51133111023 = 345613736981
BaseRepresentation
bin101111100111110001…
…010101101011101111
311212222112222011201210
4233213301111223233
51314210034023043
635253520005503
73460061162301
oct574761255357
9155875864653
1051133111023
111a75a343145
129ab0460893
134a8b744717
14269100b971
1514e40bb633
hexbe7c55aef

51133111023 has 8 divisors (see below), whose sum is σ = 68192447536. Its totient is φ = 34081257600.

The previous prime is 51133111021. The next prime is 51133111027. The reversal of 51133111023 is 32011133115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 51133111023 - 21 = 51133111021 is a prime.

It is a super-2 number, since 2×511331110232 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51133111021) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1854808 + ... + 1882173.

It is an arithmetic number, because the mean of its divisors is an integer number (8524055942).

Almost surely, 251133111023 is an apocalyptic number.

51133111023 is a deficient number, since it is larger than the sum of its proper divisors (17059336513).

51133111023 is a wasteful number, since it uses less digits than its factorization.

51133111023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3741545.

The product of its (nonzero) digits is 270, while the sum is 21.

Adding to 51133111023 its reverse (32011133115), we get a palindrome (83144244138).

The spelling of 51133111023 in words is "fifty-one billion, one hundred thirty-three million, one hundred eleven thousand, twenty-three".

Divisors: 1 3 4561 13683 3736981 11210943 17044370341 51133111023