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51133115 = 511929693
BaseRepresentation
bin1100001100001…
…1101010111011
310120012211110002
43003003222323
5101042224430
65023543215
71160424065
oct303035273
9116184402
1051133115
1126955080
121515ab0b
13a7940a7
146b10735
154750845
hex30c3abb

51133115 has 8 divisors (see below), whose sum is σ = 66937968. Its totient is φ = 37187680.

The previous prime is 51133111. The next prime is 51133171.

51133115 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 51133115 - 22 = 51133111 is a prime.

It is a super-2 number, since 2×511331152 = 5229190899206450, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51133111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 464792 + ... + 464901.

It is an arithmetic number, because the mean of its divisors is an integer number (8367246).

Almost surely, 251133115 is an apocalyptic number.

51133115 is a gapful number since it is divisible by the number (55) formed by its first and last digit.

51133115 is a deficient number, since it is larger than the sum of its proper divisors (15804853).

51133115 is a wasteful number, since it uses less digits than its factorization.

51133115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 929709.

The product of its digits is 225, while the sum is 20.

The square root of 51133115 is about 7150.7422691634. The cubic root of 51133115 is about 371.1653421298.

It can be divided in two parts, 5113 and 3115, that added together give a palindrome (8228).

The spelling of 51133115 in words is "fifty-one million, one hundred thirty-three thousand, one hundred fifteen".

Divisors: 1 5 11 55 929693 4648465 10226623 51133115