Base | Representation |
---|---|
bin | 10111010000001011000100… |
… | …01100111111110011011011 |
3 | 20201001021210221102012021100 |
4 | 23220011202030333303123 |
5 | 23200231330201424430 |
6 | 300430141050242443 |
7 | 13525153121110125 |
oct | 1350054214776333 |
9 | 221037727365240 |
10 | 51133233233115 |
11 | 15324534134aa0 |
12 | 5899b68426423 |
13 | 226bac6699617 |
14 | c8ac0c6b6215 |
15 | 5da15ceee960 |
hex | 2e816233fcdb |
51133233233115 has 48 divisors (see below), whose sum is σ = 98050102615296. Its totient is φ = 24442689364800.
The previous prime is 51133233233101. The next prime is 51133233233129.
51133233233115 is a `hidden beast` number, since 5 + 1 + 1 + 3 + 3 + 2 + 332 + 3 + 311 + 5 = 666.
51133233233115 is nontrivially palindromic in base 10.
It is an interprime number because it is at equal distance from previous prime (51133233233101) and next prime (51133233233129).
It is not a de Polignac number, because 51133233233115 - 213 = 51133233224923 is a prime.
It is a super-2 number, since 2×511332332331152 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 51133233233115.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 727425849 + ... + 727496138.
It is an arithmetic number, because the mean of its divisors is an integer number (2042710471152).
Almost surely, 251133233233115 is an apocalyptic number.
51133233233115 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
51133233233115 is a deficient number, since it is larger than the sum of its proper divisors (46916869382181).
51133233233115 is a wasteful number, since it uses less digits than its factorization.
51133233233115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1454922080 (or 1454922077 counting only the distinct ones).
The product of its digits is 72900, while the sum is 36.
It can be divided in two parts, 5113323 and 3233115, that added together give a palindrome (8346438).
The spelling of 51133233233115 in words is "fifty-one trillion, one hundred thirty-three billion, two hundred thirty-three million, two hundred thirty-three thousand, one hundred fifteen".
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