Base | Representation |
---|---|
bin | 1001100001100100… |
… | …00111101101110111 |
3 | 111012100210021020002 |
4 | 10300302013231313 |
5 | 40433013144341 |
6 | 2203222101515 |
7 | 240500201036 |
oct | 46062075567 |
9 | 14170707202 |
10 | 5113412471 |
11 | 219442a522 |
12 | ba857a89b |
13 | 6364ba26b |
14 | 36718471d |
15 | 1eddaa29b |
hex | 130c87b77 |
5113412471 has 2 divisors, whose sum is σ = 5113412472. Its totient is φ = 5113412470.
The previous prime is 5113412431. The next prime is 5113412477. The reversal of 5113412471 is 1742143115.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5113412471 is a prime.
It is a super-3 number, since 3×51134124713 (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5113412477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556706235 + 2556706236.
It is an arithmetic number, because the mean of its divisors is an integer number (2556706236).
Almost surely, 25113412471 is an apocalyptic number.
5113412471 is a deficient number, since it is larger than the sum of its proper divisors (1).
5113412471 is an equidigital number, since it uses as much as digits as its factorization.
5113412471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3360, while the sum is 29.
The square root of 5113412471 is about 71508.1287057632. The cubic root of 5113412471 is about 1722.8082472272.
Adding to 5113412471 its reverse (1742143115), we get a palindrome (6855555586).
The spelling of 5113412471 in words is "five billion, one hundred thirteen million, four hundred twelve thousand, four hundred seventy-one".
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