5113412431 has 2 divisors, whose sum is σ = 5113412432. Its totient is φ = 5113412430.

The previous prime is 5113412419. The next prime is 5113412471. The reversal of 5113412431 is 1342143115.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5113412431 - 2⁵ = 5113412399 is a prime.

It is a super-2 number, since 2×5113412431² = 52293973379010659522, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5113412396 and 5113412405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5113412401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556706215 + 2556706216.

It is an arithmetic number, because the mean of its divisors is an integer number (2556706216).

Almost surely, 2^5113412431 is an apocalyptic number.

5113412431 is a deficient number, since it is larger than the sum of its proper divisors (1).

5113412431 is an equidigital number, since it uses as much as digits as its factorization.

5113412431 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1440, while the sum is 25.

The square root of 5113412431 is about 71508.1284260748. The cubic root of 5113412431 is about 1722.8082427349.

Adding to 5113412431 its reverse (1342143115), we get a palindrome (6455555546).

The spelling of 5113412431 in words is "five billion, one hundred thirteen million, four hundred twelve thousand, four hundred thirty-one".