Base | Representation |
---|---|
bin | 10111010000001100111101… |
… | …11111111010101011000000 |
3 | 20201001101110000200121112222 |
4 | 23220012132333322223000 |
5 | 23200240422310330100 |
6 | 300430430204110212 |
7 | 13525220314601366 |
oct | 1350063677725300 |
9 | 221041400617488 |
10 | 51134253214400 |
11 | 15324a07966034 |
12 | 589a1b1b35368 |
13 | 226bc29ab1545 |
14 | c8aca7d45636 |
15 | 5da1bc82b485 |
hex | 2e819effaac0 |
51134253214400 has 42 divisors (see below), whose sum is σ = 125822221819620. Its totient is φ = 20453701285120.
The previous prime is 51134253214397. The next prime is 51134253214427. The reversal of 51134253214400 is 441235243115.
It is a super-2 number, since 2×511342532144002 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 15979452530 + ... + 15979455729.
Almost surely, 251134253214400 is an apocalyptic number.
51134253214400 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
51134253214400 is an abundant number, since it is smaller than the sum of its proper divisors (74687968605220).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51134253214400 is a wasteful number, since it uses less digits than its factorization.
51134253214400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31958908281 (or 31958908266 counting only the distinct ones).
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 51134253214400 its reverse (441235243115), we get a palindrome (51575488457515).
The spelling of 51134253214400 in words is "fifty-one trillion, one hundred thirty-four billion, two hundred fifty-three million, two hundred fourteen thousand, four hundred".
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