Search a number
-
+
511344443117 is a prime number
BaseRepresentation
bin1110111000011101000…
…00001111111011101101
31210212212110210010121102
413130032200033323231
531334213134134432
61030524114012445
751641410023464
oct7341640177355
91725773703542
10511344443117
11187950675522
1283128277125
13392b1534201
141aa6bb559db
15d47ba5e962
hex770e80feed

511344443117 has 2 divisors, whose sum is σ = 511344443118. Its totient is φ = 511344443116.

The previous prime is 511344443083. The next prime is 511344443123. The reversal of 511344443117 is 711344443115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 376233797641 + 135110645476 = 613379^2 + 367574^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-511344443117 is a prime.

It is a super-2 number, since 2×5113444431172 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (511344443917) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255672221558 + 255672221559.

It is an arithmetic number, because the mean of its divisors is an integer number (255672221559).

Almost surely, 2511344443117 is an apocalyptic number.

It is an amenable number.

511344443117 is a deficient number, since it is larger than the sum of its proper divisors (1).

511344443117 is an equidigital number, since it uses as much as digits as its factorization.

511344443117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 80640, while the sum is 38.

The spelling of 511344443117 in words is "five hundred eleven billion, three hundred forty-four million, four hundred forty-three thousand, one hundred seventeen".