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51135103 is a prime number
BaseRepresentation
bin1100001100010…
…0001001111111
310120012221011201
43003010021333
5101042310403
65024000331
71160432635
oct303041177
9116187151
1051135103
1126956618
12151600a7
13a794c76
146b11355
15475121d
hex30c427f

51135103 has 2 divisors, whose sum is σ = 51135104. Its totient is φ = 51135102.

The previous prime is 51135083. The next prime is 51135169. The reversal of 51135103 is 30153115.

51135103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 51135103 - 29 = 51134591 is a prime.

It is a super-2 number, since 2×511351032 = 5229597517641218, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51135173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25567551 + 25567552.

It is an arithmetic number, because the mean of its divisors is an integer number (25567552).

Almost surely, 251135103 is an apocalyptic number.

51135103 is a deficient number, since it is larger than the sum of its proper divisors (1).

51135103 is an equidigital number, since it uses as much as digits as its factorization.

51135103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 225, while the sum is 19.

The square root of 51135103 is about 7150.8812743605. The cubic root of 51135103 is about 371.1701522360.

Adding to 51135103 its reverse (30153115), we get a palindrome (81288218).

The spelling of 51135103 in words is "fifty-one million, one hundred thirty-five thousand, one hundred three".