Base | Representation |
---|---|
bin | 100101001101001100001… |
… | …1100010110111100111011 |
3 | 200002212000101120110112212 |
4 | 1022122120130112330323 |
5 | 1132240042033344430 |
6 | 14513050242525335 |
7 | 1035304666246106 |
oct | 112323034267473 |
9 | 20085011513485 |
10 | 5113568653115 |
11 | 16a171a21556a |
12 | 6a706396684b |
13 | 2b1290a17220 |
14 | 1396d88b973d |
15 | 8d037c87b95 |
hex | 4a698716f3b |
5113568653115 has 32 divisors (see below), whose sum is σ = 6752012359680. Its totient is φ = 3694128729984.
The previous prime is 5113568653091. The next prime is 5113568653157.
5113568653115 is nontrivially palindromic in base 10.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5113568653115 is a prime.
It is a super-2 number, since 2×51135686531152 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6272762 + ... + 7040928.
It is an arithmetic number, because the mean of its divisors is an integer number (211000386240).
Almost surely, 25113568653115 is an apocalyptic number.
5113568653115 is a deficient number, since it is larger than the sum of its proper divisors (1638443706565).
5113568653115 is a wasteful number, since it uses less digits than its factorization.
5113568653115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 770411.
The product of its digits is 1620000, while the sum is 50.
The spelling of 5113568653115 in words is "five trillion, one hundred thirteen billion, five hundred sixty-eight million, six hundred fifty-three thousand, one hundred fifteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •