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51140231 is a prime number
BaseRepresentation
bin1100001100010…
…1011010000111
310120020012012122
43003011122013
5101042441411
65024040155
71160453612
oct303053207
9116205178
1051140231
112695a45a
121516305b
13a7973bc
146b13179
1547529db
hex30c5687

51140231 has 2 divisors, whose sum is σ = 51140232. Its totient is φ = 51140230.

The previous prime is 51140213. The next prime is 51140237. The reversal of 51140231 is 13204115.

Together with previous prime (51140213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51140231 is a prime.

It is a super-2 number, since 2×511402312 = 5230646453466722, which contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51140237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25570115 + 25570116.

It is an arithmetic number, because the mean of its divisors is an integer number (25570116).

Almost surely, 251140231 is an apocalyptic number.

51140231 is a deficient number, since it is larger than the sum of its proper divisors (1).

51140231 is an equidigital number, since it uses as much as digits as its factorization.

51140231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 51140231 is about 7151.2398225762. The cubic root of 51140231 is about 371.1825592181.

Adding to 51140231 its reverse (13204115), we get a palindrome (64344346).

The spelling of 51140231 in words is "fifty-one million, one hundred forty thousand, two hundred thirty-one".