Base | Representation |
---|---|
bin | 100101001101011101010… |
… | …0011110000111101111111 |
3 | 200002220111021120201100112 |
4 | 1022122322203300331333 |
5 | 1132242230100120111 |
6 | 14513223130420235 |
7 | 1035325116265241 |
oct | 112327243607577 |
9 | 20086437521315 |
10 | 5114141020031 |
11 | 16a199330a27a |
12 | 6a71a359167b |
13 | 2b1352489284 |
14 | 13975090c091 |
15 | 8d06d147e8b |
hex | 4a6ba8f0f7f |
5114141020031 has 2 divisors, whose sum is σ = 5114141020032. Its totient is φ = 5114141020030.
The previous prime is 5114141020007. The next prime is 5114141020073. The reversal of 5114141020031 is 1300201414115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5114141020031 - 210 = 5114141019007 is a prime.
It is a super-2 number, since 2×51141410200312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5114141019979 and 5114141020006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5114141020091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557070510015 + 2557070510016.
It is an arithmetic number, because the mean of its divisors is an integer number (2557070510016).
Almost surely, 25114141020031 is an apocalyptic number.
5114141020031 is a deficient number, since it is larger than the sum of its proper divisors (1).
5114141020031 is an equidigital number, since it uses as much as digits as its factorization.
5114141020031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 480, while the sum is 23.
Adding to 5114141020031 its reverse (1300201414115), we get a palindrome (6414342434146).
The spelling of 5114141020031 in words is "five trillion, one hundred fourteen billion, one hundred forty-one million, twenty thousand, thirty-one".
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