Base | Representation |
---|---|
bin | 1100001100010… |
… | …1110110001111 |
3 | 10120020021200022 |
4 | 3003011312033 |
5 | 101043021111 |
6 | 5024052355 |
7 | 1160462063 |
oct | 303056617 |
9 | 116207608 |
10 | 51142031 |
11 | 26960846 |
12 | 151640bb |
13 | a798175 |
14 | 6b13aa3 |
15 | 47532db |
hex | 30c5d8f |
51142031 has 2 divisors, whose sum is σ = 51142032. Its totient is φ = 51142030.
The previous prime is 51142019. The next prime is 51142061. The reversal of 51142031 is 13024115.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51142031 is a prime.
It is a super-2 number, since 2×511420312 = 5231014669609922, which contains 22 as substring.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51142061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25571015 + 25571016.
It is an arithmetic number, because the mean of its divisors is an integer number (25571016).
Almost surely, 251142031 is an apocalyptic number.
51142031 is a deficient number, since it is larger than the sum of its proper divisors (1).
51142031 is an equidigital number, since it uses as much as digits as its factorization.
51142031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 17.
The square root of 51142031 is about 7151.3656737717. The cubic root of 51142031 is about 371.1869140463.
Adding to 51142031 its reverse (13024115), we get a palindrome (64166146).
The spelling of 51142031 in words is "fifty-one million, one hundred forty-two thousand, thirty-one".
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