5114214121 has 2 divisors, whose sum is σ = 5114214122. Its totient is φ = 5114214120.

The previous prime is 5114214113. The next prime is 5114214137. The reversal of 5114214121 is 1214124115.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3356927721 + 1757286400 = 57939^2 + 41920^2 .

It is a cyclic number.

It is not a de Polignac number, because 5114214121 - 2³ = 5114214113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5114214092 and 5114214101.

It is not a weakly prime, because it can be changed into another prime (5114214221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557107060 + 2557107061.

It is an arithmetic number, because the mean of its divisors is an integer number (2557107061).

Almost surely, 2^5114214121 is an apocalyptic number.

It is an amenable number.

5114214121 is a deficient number, since it is larger than the sum of its proper divisors (1).

5114214121 is an equidigital number, since it uses as much as digits as its factorization.

5114214121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 320, while the sum is 22.

The square root of 5114214121 is about 71513.7337928876. The cubic root of 5114214121 is about 1722.8982730219.

Adding to 5114214121 its reverse (1214124115), we get a palindrome (6328338236).

The spelling of 5114214121 in words is "five billion, one hundred fourteen million, two hundred fourteen thousand, one hundred twenty-one".