Base | Representation |
---|---|
bin | 10111010000011011111110… |
… | …10011001010100111010011 |
3 | 20201002011020121102222222221 |
4 | 23220031333103022213103 |
5 | 23200403423144332430 |
6 | 300434241541241511 |
7 | 13525624102443544 |
oct | 1350157723124723 |
9 | 221064217388887 |
10 | 51142311324115 |
11 | 15328372513140 |
12 | 589b880703297 |
13 | 226c91238c0bb |
14 | c8b4302184cb |
15 | 5da4deea457a |
hex | 2e837f4ca9d3 |
51142311324115 has 64 divisors (see below), whose sum is σ = 69381545587200. Its totient is φ = 35867973657600.
The previous prime is 51142311324031. The next prime is 51142311324131.
51142311324115 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 51142311324115 - 29 = 51142311323603 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 72084576 + ... + 72790594.
It is an arithmetic number, because the mean of its divisors is an integer number (1084086649800).
Almost surely, 251142311324115 is an apocalyptic number.
51142311324115 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
51142311324115 is a deficient number, since it is larger than the sum of its proper divisors (18239234263085).
51142311324115 is a wasteful number, since it uses less digits than its factorization.
51142311324115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 706468.
The product of its digits is 14400, while the sum is 34.
It can be divided in two parts, 5114231 and 1324115, that added together give a palindrome (6438346).
The spelling of 51142311324115 in words is "fifty-one trillion, one hundred forty-two billion, three hundred eleven million, three hundred twenty-four thousand, one hundred fifteen".
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