Base | Representation |
---|---|
bin | 10111010000011100001001… |
… | …00111000011100010110011 |
3 | 20201002011110211002202012221 |
4 | 23220032010213003202303 |
5 | 23200404114002032430 |
6 | 300434254443101511 |
7 | 13525626234000400 |
oct | 1350160447034263 |
9 | 221064424082187 |
10 | 51142400424115 |
11 | 1532840883a300 |
12 | 589b8a6511897 |
13 | 226c9279874b0 |
14 | c8b43bdad2a7 |
15 | 5da4e7c0457a |
hex | 2e83849c38b3 |
51142400424115 has 144 divisors (see below), whose sum is σ = 84949449822720. Its totient is φ = 29274475507200.
The previous prime is 51142400424109. The next prime is 51142400424131.
51142400424115 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 51142400424115 - 25 = 51142400424083 is a prime.
It is a super-2 number, since 2×511424004241152 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 73261141 + ... + 73955929.
It is an arithmetic number, because the mean of its divisors is an integer number (589926734880).
Almost surely, 251142400424115 is an apocalyptic number.
51142400424115 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
51142400424115 is a deficient number, since it is larger than the sum of its proper divisors (33807049398605).
51142400424115 is a wasteful number, since it uses less digits than its factorization.
51142400424115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 695034 (or 695016 counting only the distinct ones).
The product of its (nonzero) digits is 25600, while the sum is 34.
It can be divided in two parts, 51142400 and 424115, that added together give a palindrome (51566515).
The spelling of 51142400424115 in words is "fifty-one trillion, one hundred forty-two billion, four hundred million, four hundred twenty-four thousand, one hundred fifteen".
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