5114255444301 has 8 divisors (see below), whose sum is σ = 6819601140000. Its totient is φ = 3409206689072.

The previous prime is 5114255444293. The next prime is 5114255444327. The reversal of 5114255444301 is 1034445524115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5114255444301 - 2³ = 5114255444293 is a prime.

It is a super-3 number, since 3×5114255444301³ (a number of 39 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 5114255444301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5114255444381) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 74194926 + ... + 74263823.

It is an arithmetic number, because the mean of its divisors is an integer number (852450142500).

Almost surely, 2^{5114255444301} is an apocalyptic number.

It is an amenable number.

5114255444301 is a deficient number, since it is larger than the sum of its proper divisors (1705345695699).

5114255444301 is a wasteful number, since it uses less digits than its factorization.

5114255444301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 148470235.

The product of its (nonzero) digits is 192000, while the sum is 39.

The spelling of 5114255444301 in words is "five trillion, one hundred fourteen billion, two hundred fifty-five million, four hundred forty-four thousand, three hundred one".