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5114441 = 23222367
BaseRepresentation
bin10011100000101001001001
3100121211200202
4103200221021
52302130231
6301341545
761320623
oct23405111
910554622
105114441
112983612
1218678b5
1310a0bc7
14971c13
156b05cb
hex4e0a49

5114441 has 4 divisors (see below), whose sum is σ = 5336832. Its totient is φ = 4892052.

The previous prime is 5114437. The next prime is 5114443. The reversal of 5114441 is 1444115.

5114441 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1444115 = 5288823.

It is a cyclic number.

It is not a de Polignac number, because 5114441 - 22 = 5114437 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5114443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111161 + ... + 111206.

It is an arithmetic number, because the mean of its divisors is an integer number (1334208).

Almost surely, 25114441 is an apocalyptic number.

It is an amenable number.

5114441 is a deficient number, since it is larger than the sum of its proper divisors (222391).

5114441 is a wasteful number, since it uses less digits than its factorization.

5114441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 222390.

The product of its digits is 320, while the sum is 20.

The square root of 5114441 is about 2261.5129891292. The cubic root of 5114441 is about 172.2923749967.

Adding to 5114441 its reverse (1444115), we get a palindrome (6558556).

It can be divided in two parts, 5114 and 441, that added together give a palindrome (5555).

The spelling of 5114441 in words is "five million, one hundred fourteen thousand, four hundred forty-one".

Divisors: 1 23 222367 5114441