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51150130051 = 72770357813
BaseRepresentation
bin101111101000110010…
…010000101110000011
311220000201222211110011
4233220302100232003
51314223413130201
635255324445351
73460355634406
oct575062205603
9156021884404
1051150130051
111a768a07859
129ab60a9857
134a92123057
14269339bd3d
1514e582e151
hexbe8c90b83

51150130051 has 4 divisors (see below), whose sum is σ = 51220488592. Its totient is φ = 51079771512.

The previous prime is 51150130037. The next prime is 51150130117. The reversal of 51150130051 is 15003105115.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 51150130051 - 25 = 51150130019 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51150130021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35178180 + ... + 35179633.

It is an arithmetic number, because the mean of its divisors is an integer number (12805122148).

Almost surely, 251150130051 is an apocalyptic number.

51150130051 is a deficient number, since it is larger than the sum of its proper divisors (70358541).

51150130051 is an equidigital number, since it uses as much as digits as its factorization.

51150130051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70358540.

The product of its (nonzero) digits is 375, while the sum is 22.

Adding to 51150130051 its reverse (15003105115), we get a palindrome (66153235166).

The spelling of 51150130051 in words is "fifty-one billion, one hundred fifty million, one hundred thirty thousand, fifty-one".

Divisors: 1 727 70357813 51150130051