Base | Representation |
---|---|
bin | 100101001101111010111… |
… | …0011100000011001011011 |
3 | 200010000001112221020120001 |
4 | 1022123311303200121123 |
5 | 1132301244030032303 |
6 | 14513505515113431 |
7 | 1035361546063402 |
oct | 112336563403133 |
9 | 20100045836501 |
10 | 5115135002203 |
11 | 16a23533a2846 |
12 | 6a7420442877 |
13 | 2b148039a2c5 |
14 | 139806930639 |
15 | 8d0ca53b31d |
hex | 4a6f5ce065b |
5115135002203 has 2 divisors, whose sum is σ = 5115135002204. Its totient is φ = 5115135002202.
The previous prime is 5115135002183. The next prime is 5115135002221. The reversal of 5115135002203 is 3022005315115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5115135002203 - 25 = 5115135002171 is a prime.
It is not a weakly prime, because it can be changed into another prime (5115135002273) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557567501101 + 2557567501102.
It is an arithmetic number, because the mean of its divisors is an integer number (2557567501102).
Almost surely, 25115135002203 is an apocalyptic number.
5115135002203 is a deficient number, since it is larger than the sum of its proper divisors (1).
5115135002203 is an equidigital number, since it uses as much as digits as its factorization.
5115135002203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4500, while the sum is 28.
The spelling of 5115135002203 in words is "five trillion, one hundred fifteen billion, one hundred thirty-five million, two thousand, two hundred three".
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