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51154104373 is a prime number
BaseRepresentation
bin101111101001000001…
…011011000000110101
311220001000110202012021
4233221001123000311
51314230422314443
635255545553141
73460434466351
oct575101330065
9156030422167
1051154104373
111a770181819
129ab74a57b1
134a92bb5018
142693b14461
1514e5d669ed
hexbe905b035

51154104373 has 2 divisors, whose sum is σ = 51154104374. Its totient is φ = 51154104372.

The previous prime is 51154104311. The next prime is 51154104427. The reversal of 51154104373 is 37340145115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47079452484 + 4074651889 = 216978^2 + 63833^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51154104373 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51154101373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25577052186 + 25577052187.

It is an arithmetic number, because the mean of its divisors is an integer number (25577052187).

Almost surely, 251154104373 is an apocalyptic number.

It is an amenable number.

51154104373 is a deficient number, since it is larger than the sum of its proper divisors (1).

51154104373 is an equidigital number, since it uses as much as digits as its factorization.

51154104373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25200, while the sum is 34.

Adding to 51154104373 its reverse (37340145115), we get a palindrome (88494249488).

The spelling of 51154104373 in words is "fifty-one billion, one hundred fifty-four million, one hundred four thousand, three hundred seventy-three".