Base | Representation |
---|---|
bin | 100101001110000100101… |
… | …1111001101100000111111 |
3 | 200010000220120022100212021 |
4 | 1022130021133031200333 |
5 | 1132302433044220203 |
6 | 14514002353021011 |
7 | 1035402665664025 |
oct | 112341137154077 |
9 | 20100816270767 |
10 | 5115465226303 |
11 | 16a2502840023 |
12 | 6a74b2b54767 |
13 | 2b150391b093 |
14 | 139838730715 |
15 | 8d0e951a5bd |
hex | 4a7097cd83f |
5115465226303 has 2 divisors, whose sum is σ = 5115465226304. Its totient is φ = 5115465226302.
The previous prime is 5115465226273. The next prime is 5115465226321. The reversal of 5115465226303 is 3036225645115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5115465226303 - 217 = 5115465095231 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5115465226303.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5115465226603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557732613151 + 2557732613152.
It is an arithmetic number, because the mean of its divisors is an integer number (2557732613152).
Almost surely, 25115465226303 is an apocalyptic number.
5115465226303 is a deficient number, since it is larger than the sum of its proper divisors (1).
5115465226303 is an equidigital number, since it uses as much as digits as its factorization.
5115465226303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648000, while the sum is 43.
The spelling of 5115465226303 in words is "five trillion, one hundred fifteen billion, four hundred sixty-five million, two hundred twenty-six thousand, three hundred three".
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