Base | Representation |
---|---|
bin | 1001100010000000… |
… | …11000010111100101 |
3 | 111012121211012002202 |
4 | 10301000120113211 |
5 | 40434442310233 |
6 | 2203434144245 |
7 | 240544030454 |
oct | 46100302745 |
9 | 14177735082 |
10 | 5117150693 |
11 | 2196553066 |
12 | ba9882085 |
13 | 6371c8925 |
14 | 367878b9b |
15 | 1ee397be8 |
hex | 1310185e5 |
5117150693 has 2 divisors, whose sum is σ = 5117150694. Its totient is φ = 5117150692.
The previous prime is 5117150677. The next prime is 5117150713. The reversal of 5117150693 is 3960517115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4676234689 + 440916004 = 68383^2 + 20998^2 .
It is a cyclic number.
It is not a de Polignac number, because 5117150693 - 24 = 5117150677 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5117150663) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2558575346 + 2558575347.
It is an arithmetic number, because the mean of its divisors is an integer number (2558575347).
Almost surely, 25117150693 is an apocalyptic number.
It is an amenable number.
5117150693 is a deficient number, since it is larger than the sum of its proper divisors (1).
5117150693 is an equidigital number, since it uses as much as digits as its factorization.
5117150693 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28350, while the sum is 38.
The square root of 5117150693 is about 71534.2623712582. The cubic root of 5117150693 is about 1723.2279715607.
The spelling of 5117150693 in words is "five billion, one hundred seventeen million, one hundred fifty thousand, six hundred ninety-three".
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