Base | Representation |
---|---|
bin | 101111101010001001… |
… | …100000001101110111 |
3 | 11220002100000202012100 |
4 | 233222021200031313 |
5 | 1314300242000210 |
6 | 35301502553143 |
7 | 3461054215662 |
oct | 575211401567 |
9 | 156070022170 |
10 | 51173000055 |
11 | 1a77a908391 |
12 | 9b018987b3 |
13 | 4a96a9c8b8 |
14 | 26964326d9 |
15 | 14e784a5c0 |
hex | bea260377 |
51173000055 has 12 divisors (see below), whose sum is σ = 88699866840. Its totient is φ = 27292266672.
The previous prime is 51173000051. The next prime is 51173000071. The reversal of 51173000055 is 55000037115.
It is not a de Polignac number, because 51173000055 - 22 = 51173000051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 51172999992 and 51173000028.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51173000051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 568588845 + ... + 568588934.
It is an arithmetic number, because the mean of its divisors is an integer number (7391655570).
Almost surely, 251173000055 is an apocalyptic number.
51173000055 is a deficient number, since it is larger than the sum of its proper divisors (37526866785).
51173000055 is a wasteful number, since it uses less digits than its factorization.
51173000055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1137177790 (or 1137177787 counting only the distinct ones).
The product of its (nonzero) digits is 2625, while the sum is 27.
The spelling of 51173000055 in words is "fifty-one billion, one hundred seventy-three million, fifty-five", and thus it is an aban number.
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