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5120150341 is a prime number
BaseRepresentation
bin1001100010010111…
…10100101101000101
3111012211110120211211
410301023310231011
540441224302331
62204022331421
7240611363005
oct46113645505
914184416754
105120150341
112198211809
12baa889b71
13637a09077
1436801a005
151ee78b8b1
hex1312f4b45

5120150341 has 2 divisors, whose sum is σ = 5120150342. Its totient is φ = 5120150340.

The previous prime is 5120150311. The next prime is 5120150407. The reversal of 5120150341 is 1430510215.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2859147841 + 2261002500 = 53471^2 + 47550^2 .

It is a cyclic number.

It is not a de Polignac number, because 5120150341 - 29 = 5120149829 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5120150311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560075170 + 2560075171.

It is an arithmetic number, because the mean of its divisors is an integer number (2560075171).

Almost surely, 25120150341 is an apocalyptic number.

It is an amenable number.

5120150341 is a deficient number, since it is larger than the sum of its proper divisors (1).

5120150341 is an equidigital number, since it uses as much as digits as its factorization.

5120150341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 600, while the sum is 22.

The square root of 5120150341 is about 71555.2258119559. The cubic root of 5120150341 is about 1723.5646216451.

Adding to 5120150341 its reverse (1430510215), we get a palindrome (6550660556).

The spelling of 5120150341 in words is "five billion, one hundred twenty million, one hundred fifty thousand, three hundred forty-one".