Base | Representation |
---|---|
bin | 101111101011111000… |
… | …010111101100011110 |
3 | 11220011100201022020200 |
4 | 233223320113230132 |
5 | 1314330212010014 |
6 | 35304421524330 |
7 | 3461556232665 |
oct | 575370275436 |
9 | 156140638220 |
10 | 51202063134 |
11 | 1a795258962 |
12 | 9b0b5736a6 |
13 | 4a9cb072a1 |
14 | 269a239ddc |
15 | 14ea18ba09 |
hex | bebe17b1e |
51202063134 has 24 divisors (see below), whose sum is σ = 115761187152. Its totient is φ = 16325295360.
The previous prime is 51202063103. The next prime is 51202063183. The reversal of 51202063134 is 43136020215.
51202063134 is a `hidden beast` number, since 5 + 1 + 2 + 0 + 20 + 631 + 3 + 4 = 666.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 51202063098 and 51202063107.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 61837827 + ... + 61838654.
It is an arithmetic number, because the mean of its divisors is an integer number (4823382798).
Almost surely, 251202063134 is an apocalyptic number.
51202063134 is an abundant number, since it is smaller than the sum of its proper divisors (64559124018).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51202063134 is a wasteful number, since it uses less digits than its factorization.
51202063134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 123676512 (or 123676509 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 27.
Adding to 51202063134 its reverse (43136020215), we get a palindrome (94338083349).
The spelling of 51202063134 in words is "fifty-one billion, two hundred two million, sixty-three thousand, one hundred thirty-four".
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