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51204043306103 = 101506970725803
BaseRepresentation
bin10111010010001110111101…
…10011111111010001110111
320201022001120211001121101012
423221013132303333101313
523202411340041243403
6300522451320022435
713533240632565452
oct1351073663772167
9221261524047335
1051204043306103
1115351570617976
1258ab82a601a1b
13227569c8b29ac
14c90408b1a499
155dbe047c6ed8
hex2e91decff477

51204043306103 has 4 divisors (see below), whose sum is σ = 51711014032008. Its totient is φ = 50697072580200.

The previous prime is 51204043306081. The next prime is 51204043306109. The reversal of 51204043306103 is 30160334040215.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 51204043306103 - 28 = 51204043305847 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 51204043306103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51204043306109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 253485362801 + ... + 253485363002.

It is an arithmetic number, because the mean of its divisors is an integer number (12927753508002).

Almost surely, 251204043306103 is an apocalyptic number.

51204043306103 is a deficient number, since it is larger than the sum of its proper divisors (506970725905).

51204043306103 is a wasteful number, since it uses less digits than its factorization.

51204043306103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 506970725904.

The product of its (nonzero) digits is 25920, while the sum is 32.

Adding to 51204043306103 its reverse (30160334040215), we get a palindrome (81364377346318).

The spelling of 51204043306103 in words is "fifty-one trillion, two hundred four billion, forty-three million, three hundred six thousand, one hundred three".

Divisors: 1 101 506970725803 51204043306103