Base | Representation |
---|---|
bin | 101111101100100011… |
… | …000000011011100001 |
3 | 11220012010202011001220 |
4 | 233230203000123201 |
5 | 1314341042140113 |
6 | 35305501245253 |
7 | 3462053233464 |
oct | 575443003341 |
9 | 156163664056 |
10 | 51213240033 |
11 | 1a7a05a226a |
12 | 9b13263829 |
13 | 4aa221b737 |
14 | 269b9092db |
15 | 14eb148523 |
hex | bec8c06e1 |
51213240033 has 8 divisors (see below), whose sum is σ = 68320476000. Its totient is φ = 34124082048.
The previous prime is 51213239989. The next prime is 51213240041. The reversal of 51213240033 is 33004231215.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 51213240033 - 213 = 51213231841 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 51213239985 and 51213240012.
It is not an unprimeable number, because it can be changed into a prime (51213245033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4512883 + ... + 4524216.
It is an arithmetic number, because the mean of its divisors is an integer number (8540059500).
Almost surely, 251213240033 is an apocalyptic number.
It is an amenable number.
51213240033 is a deficient number, since it is larger than the sum of its proper divisors (17107235967).
51213240033 is a wasteful number, since it uses less digits than its factorization.
51213240033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9038991.
The product of its (nonzero) digits is 2160, while the sum is 24.
Adding to 51213240033 its reverse (33004231215), we get a palindrome (84217471248).
The spelling of 51213240033 in words is "fifty-one billion, two hundred thirteen million, two hundred forty thousand, thirty-three".
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