Base | Representation |
---|---|
bin | 1001100010100000… |
… | …11000010111010111 |
3 | 111012220201021120211 |
4 | 10301100120113113 |
5 | 40442031014413 |
6 | 2204104110251 |
7 | 240624466636 |
oct | 46120302727 |
9 | 14186637524 |
10 | 5121344983 |
11 | 2198958317 |
12 | bab165387 |
13 | 638036a61 |
14 | 36824b51d |
15 | 1ee92583d |
hex | 1314185d7 |
5121344983 has 2 divisors, whose sum is σ = 5121344984. Its totient is φ = 5121344982.
The previous prime is 5121344951. The next prime is 5121344999. The reversal of 5121344983 is 3894431215.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5121344983 - 25 = 5121344951 is a prime.
It is a super-3 number, since 3×51213449833 (a number of 30 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5121344903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560672491 + 2560672492.
It is an arithmetic number, because the mean of its divisors is an integer number (2560672492).
Almost surely, 25121344983 is an apocalyptic number.
5121344983 is a deficient number, since it is larger than the sum of its proper divisors (1).
5121344983 is an equidigital number, since it uses as much as digits as its factorization.
5121344983 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 103680, while the sum is 40.
The square root of 5121344983 is about 71563.5730172830. The cubic root of 5121344983 is about 1723.6986595431.
The spelling of 5121344983 in words is "five billion, one hundred twenty-one million, three hundred forty-four thousand, nine hundred eighty-three".
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