Base | Representation |
---|---|
bin | 100101010001000000101… |
… | …1101100101111100100111 |
3 | 200010122012011120021002211 |
4 | 1022202001131211330213 |
5 | 1132403342344112203 |
6 | 14520524323144251 |
7 | 1036015211324521 |
oct | 112420135457447 |
9 | 20118164507084 |
10 | 5121773035303 |
11 | 16a514a399311 |
12 | 6a8773515087 |
13 | 2b1c9a6ba142 |
14 | 139c76386a11 |
15 | 8d3681a5c6d |
hex | 4a881765f27 |
5121773035303 has 4 divisors (see below), whose sum is σ = 5240884036168. Its totient is φ = 5002662034440.
The previous prime is 5121773035273. The next prime is 5121773035307. The reversal of 5121773035303 is 3035303771215.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5121773035303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5121773035307) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59555500368 + ... + 59555500453.
It is an arithmetic number, because the mean of its divisors is an integer number (1310221009042).
Almost surely, 25121773035303 is an apocalyptic number.
5121773035303 is a deficient number, since it is larger than the sum of its proper divisors (119111000865).
5121773035303 is a wasteful number, since it uses less digits than its factorization.
5121773035303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 119111000864.
The product of its (nonzero) digits is 198450, while the sum is 40.
The spelling of 5121773035303 in words is "five trillion, one hundred twenty-one billion, seven hundred seventy-three million, thirty-five thousand, three hundred three".
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