Base | Representation |
---|---|
bin | 100101010001001011011… |
… | …1100011111000101011111 |
3 | 200010200010021202111020212 |
4 | 1022202112330133011133 |
5 | 1132410112131031244 |
6 | 14521024200203035 |
7 | 1036030146000425 |
oct | 112422674370537 |
9 | 20120107674225 |
10 | 5122133455199 |
11 | 16a53148900a2 |
12 | 6a885416947b |
13 | 2b2027281057 |
14 | 139cac1a7115 |
15 | 8d389b4bd9e |
hex | 4a896f1f15f |
5122133455199 has 2 divisors, whose sum is σ = 5122133455200. Its totient is φ = 5122133455198.
The previous prime is 5122133455189. The next prime is 5122133455249. The reversal of 5122133455199 is 9915543312215.
It is an a-pointer prime, because the next prime (5122133455249) can be obtained adding 5122133455199 to its sum of digits (50).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5122133455199 - 24 = 5122133455183 is a prime.
It is a super-2 number, since 2×51221334551992 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5122133455129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2561066727599 + 2561066727600.
It is an arithmetic number, because the mean of its divisors is an integer number (2561066727600).
Almost surely, 25122133455199 is an apocalyptic number.
5122133455199 is a deficient number, since it is larger than the sum of its proper divisors (1).
5122133455199 is an equidigital number, since it uses as much as digits as its factorization.
5122133455199 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1458000, while the sum is 50.
The spelling of 5122133455199 in words is "five trillion, one hundred twenty-two billion, one hundred thirty-three million, four hundred fifty-five thousand, one hundred ninety-nine".
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